document.write( "Question 431533: x^2+6x-2=(x+p)^2+q find values of p and q please help the answer is p=3 and q=11, but tried to workd out but dont know how thanks \n" ); document.write( "
Algebra.Com's Answer #299465 by sudhanshu_kmr(1152)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "x^2+6x-2 = (x+p)^2+q\r
\n" ); document.write( "\n" ); document.write( "=> x^2+6x-2= x^2 +p^2 + 2px + q\r
\n" ); document.write( "\n" ); document.write( "now, compare co-efficient of both sides....\r
\n" ); document.write( "\n" ); document.write( "co-efficient of x on LHS = 6, on RHS = 2p \r
\n" ); document.write( "\n" ); document.write( "so, 6 = 2p\r
\n" ); document.write( "\n" ); document.write( "=> p = 3\r
\n" ); document.write( "\n" ); document.write( "similarly constant value on LHS is -2, on RHS is p^2 +q \r
\n" ); document.write( "\n" ); document.write( "so, -2 = p^2 +q\r
\n" ); document.write( "\n" ); document.write( "=> -2 = 3^2 + q (after putting the value of p)\r
\n" ); document.write( "\n" ); document.write( "=> -2 -9 = q\r
\n" ); document.write( "\n" ); document.write( "here q = -11\r
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\n" ); document.write( "\n" ); document.write( "p = 3 and q = -11\r
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