document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=431487>Question 431487</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One number is 5 times as large as another. The sum of their reciprocals is 3/5. What are the numbers? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #299449 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=299449\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = the smaller number<BR>\n" );
document.write( "Then the larger number = 5x<BR>\n" );
document.write( "Given: the sum of their reciprocals = 3/5<BR>\n" );
document.write( "In equation form this is:<BR>\n" );
document.write( "1/x + 1/(5x) = 3/5<BR>\n" );
document.write( "Multiply through by x:<BR>\n" );
document.write( "1 + 1/5 = (3/5)x -> (3/5)x = 6/5 -> x = (5/3)(6/5) = 2<BR>\n" );
document.write( "So the other number = 5*2 = 10<BR>\n" );
document.write( "Ans: 2, 10 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );