document.write( "Question 431388: A boat moves 7 km upstream in the same amount of time it moves 20 km downstream.
\n" ); document.write( "if the rate of the current is 6 km per hour, find the rate of the boat in still water.
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Algebra.Com's Answer #299390 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi
\n" ); document.write( "Let x represent the rate of the boat in still water.
\n" ); document.write( "Question states*** Note t = D/r (times the same)
\n" ); document.write( "\"+7km%2F%28x-6%29+=+20km%2F%28x%2B6%29+\" | Cross Multiplying
\n" ); document.write( " 7(x+6) = 20(x-6)
\n" ); document.write( " 162 = 13x
\n" ); document.write( " x = 12.4615kmph
\n" ); document.write( "CHECKING our Answer***
\n" ); document.write( " 7/6.4615 = 20/18.4615 = 1.0833 \n" ); document.write( "
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