document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=431344>Question 431344</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Ann and Nancy use a metal alloy that is 17.3% copper to make jewelry. how many ounces of a 17% alloy must be mixed with a 18% alloy to form 80 ounces of the desired alloy? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #299378 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=299378\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 	percent	----------------quantity							<BR>\n" );
document.write( "Alloy I	17	----------------x	ounces						<BR>\n" );
document.write( "Alloy II 18	----------------80-x	ounces						<BR>\n" );
document.write( "Total	17.30%	----------------	80 ounces<BR>\n" );
document.write( "17x+18(80-x)=17.3*80<BR>\n" );
document.write( "17x+1440-18x=1384		<BR>\n" );
document.write( "17x-18x	=1384-1440		<BR>\n" );
document.write( "-x=-56							<BR>\n" );
document.write( "x=56	ounces		17.00%		<BR>\n" );
document.write( "24	ounces		18.00%		<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );