document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=431148>Question 431148</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Show an evaluation of sin 120 degrees using the trigonometric addition formulas.\r<BR>\n" );
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document.write( "Show an evaluation of sin 120 degrees using the double-angle formulas. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #299367 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=299367\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Show an evaluation of sin 120 degrees using the trigonometric addition formulas. <BR>\n" );
document.write( "Show an evaluation of sin 120 degrees using the double-angle formulas...<BR>\n" );
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document.write( "Addition formula:<BR>\n" );
document.write( "sin(x+y)=sinxcosy+cosxsiny<BR>\n" );
document.write( "sin120=sin(60+60)<BR>\n" );
document.write( "           =sin60cos60+cos60sin60<BR>\n" );
document.write( "           =(sqrt(3)/2)(1/2+(1/2)(sqrt(3)/2)<BR>\n" );
document.write( "           =(sqrt(3)/2)\r<BR>\n" );
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document.write( "..\r<BR>\n" );
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document.write( "Double angle formula:<BR>\n" );
document.write( "Sin2x=2sinxcosx<BR>\n" );
document.write( "Sin120=2sin60cos60<BR>\n" );
document.write( "           =2(sqrt3/2)(1/2)<BR>\n" );
document.write( "           =(sqrt3/2)<BR>\n" );
document.write( "     </SPAN>\n" );
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