document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=45094>Question 45094</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One number is 2 times another. If the sum of their reciprocal is 1/4, find the two numbers.\r<BR>\n" );
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document.write( " Thank You!!!!  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #29936 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=29936\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> One number is 2 times another. If the sum of their reciprocal is 1/4, find the two numbers.\r<BR>\n" );
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document.write( "Let one of the numbers be \"x\"<BR>\n" );
document.write( "The other is \"2x\"<BR>\n" );
document.write( "EQUATION:<BR>\n" );
document.write( "1/x + 1/2x = 1/4\r<BR>\n" );
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document.write( "(2x+x)/2x^2 = 1/4\r<BR>\n" );
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document.write( "3x/2x^2 = 1/4<BR>\n" );
document.write( "3/2x=1/4<BR>\n" );
document.write( "2x=12 (one of the numbers)<BR>\n" );
document.write( "x=6 (the other number)\r<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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