document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=431227>Question 431227</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One whole number is three times a second if 20 is added to the smaller number, the result equals 6 more than the larger number. Find both numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #299322 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=299322\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> \"One whole number is three times a second if 20 is added to the smaller number, the result equals 6 more than the larger number. Find both numbers.\"\r<BR>\n" );
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document.write( "x = one number<BR>\n" );
document.write( "3x = other number {one number is three times a second}\r<BR>\n" );
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document.write( "x + 20 = 3x + 6 {twenty added to smaller is six more than larger}<BR>\n" );
document.write( "x + 14 = 3x {subtracted 6 from both sides}<BR>\n" );
document.write( "2x = 14 {subtracted x from both sides}<BR>\n" );
document.write( "x = 7 {divided both sides by 2}<BR>\n" );
document.write( "3x = 21 {substituted 7, in for x, into 3x}\r<BR>\n" );
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document.write( "7 and 21 are the two numbers<BR>\n" );
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document.write( " </SPAN>\n" );
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