document.write( "Question 430827: the length of a rectangle is 50ft. The perimeter of the rectangle is 275ft more than the width of the rectangle. find the width. I'm stumped, it's been years since i tried this and I feel stupid lol thanks for the help \n" ); document.write( "
Algebra.Com's Answer #299300 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! the length of a rectangle is 50ft. \n" ); document.write( " The perimeter of the rectangle is 275ft more than the width of the rectangle. \n" ); document.write( " find the width. \n" ); document.write( ": \n" ); document.write( "Let W = the width \n" ); document.write( ": \n" ); document.write( "The perimeter equation \n" ); document.write( "2L + 2W = 275 + W \n" ); document.write( "we know the length is 50, so twice that, we have \n" ); document.write( "100 + 2W = 275 + W \n" ); document.write( "2W - W = 275 - 100 \n" ); document.write( "W = 175 ft is the width \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check that, the perimeter = 175 + 275 = 450 ft \n" ); document.write( "2(50) + 2(175) = \n" ); document.write( "100 + 350 = 450 \n" ); document.write( " \n" ); document.write( " |