document.write( "Question 430827: the length of a rectangle is 50ft. The perimeter of the rectangle is 275ft more than the width of the rectangle. find the width. I'm stumped, it's been years since i tried this and I feel stupid lol thanks for the help \n" ); document.write( "
Algebra.Com's Answer #299300 by ankor@dixie-net.com(22740)\"\" \"About 
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the length of a rectangle is 50ft.
\n" ); document.write( " The perimeter of the rectangle is 275ft more than the width of the rectangle.
\n" ); document.write( " find the width.
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\n" ); document.write( "Let W = the width
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\n" ); document.write( "The perimeter equation
\n" ); document.write( "2L + 2W = 275 + W
\n" ); document.write( "we know the length is 50, so twice that, we have
\n" ); document.write( "100 + 2W = 275 + W
\n" ); document.write( "2W - W = 275 - 100
\n" ); document.write( "W = 175 ft is the width
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\n" ); document.write( "Check that, the perimeter = 175 + 275 = 450 ft
\n" ); document.write( "2(50) + 2(175) =
\n" ); document.write( "100 + 350 = 450
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