document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=431020>Question 431020</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Im having trouble figuring out this problem. I attempted to figure out the LCM but really got nowhere. \r<BR>\n" );
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document.write( "((6x+7)/(4x-1))=((3x+8)/(2x-4))\r<BR>\n" );
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document.write( "I would be grateful for any help. Thank you!  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #299250 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley79><B>checkley79(3341)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley79><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=299250\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> ((6x+7)/(4x-1))=((3x+8)/(2x-4))<BR>\n" );
document.write( "For this type of problem you don't need an LCM.<BR>\n" );
document.write( "First you should cross multiply.<BR>\n" );
document.write( "(4x-1)(3x+8)=(6x+7)(2x-4) Then expand.<BR>\n" );
document.write( "12x^2-3x+32x-8=12x^2+14x-24x-28 Combine like terms.<BR>\n" );
document.write( "12x^2+29x-8=12x^2-10x-28 <BR>\n" );
document.write( "12x^2-12x^2+29x+10x=8-28<BR>\n" );
document.write( "39x=-20<BR>\n" );
document.write( "x=-20/39 ans.\r<BR>\n" );
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