document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=431020>Question 431020</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Im having trouble figuring out this problem. I attempted to figure out the LCM but really got nowhere. \r<BR>\n" );
document.write( "\n" );
document.write( "((6x+7)/(4x-1))=((3x+8)/(2x-4))\r<BR>\n" );
document.write( "\n" );
document.write( "I would be grateful for any help. Thank you!  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #299248 by </B><A HREF=/tutors/aboutme.mpl?userid=shree840><B>shree840(260)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=shree840><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=shree840><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=299248\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (6x+7)/(4x-1)=(3x+8)/2x-4)<BR>\n" );
document.write( "cross multiply<BR>\n" );
document.write( "(6x+7)(2x-4)=(3x+8)(4x-1)<BR>\n" );
document.write( "12x^2-24x+14x-28=12x^2-3x+32x-8<BR>\n" );
document.write( "12 x^2 cancels<BR>\n" );
document.write( "-10x-28=29x-8<BR>\n" );
document.write( "-39x=20<BR>\n" );
document.write( "x=-20/39  ANS </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );