document.write( "Question 430926: Show or graph work
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Algebra.Com's Answer #299247 by jorel1380(3719)\"\" \"About 
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Solved by pluggable solver: DESCRIBE a linear EQUATION: slope, intercepts, etc
Equation \"1+x+%2B+-2+y+=+2\" describes a sloping line. For any
\n" ); document.write( " equation ax+by+c = 0, slope is \"-a%2Fb+=+-1%2F-2\".
  • X intercept is found by setting y to 0: ax+by=c becomes ax=c. that means that x = c/a. 2/1 = 2.
  • Y intercept is found by setting x to 0: the equation becomes by=c, and therefore y = c/b. Y intercept is 2/-2 = -1.
  • Slope is -1/-2 = 0.5.
  • Equation in slope-intercept form: y=0.5*x+-1.
\"graph%28+500%2C+500%2C+2-8%2C+2%2B8%2C+-1-8%2C+-1%2B8%2C+0.5%2Ax%2B-1+%29+\"\n" ); document.write( "

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Solved by pluggable solver: DESCRIBE a linear EQUATION: slope, intercepts, etc
Equation \"1+x+%2B+-1+y+=+0\" describes a sloping line. For any
\n" ); document.write( " equation ax+by+c = 0, slope is \"-a%2Fb+=+-1%2F-1\".
  • X intercept is found by setting y to 0: ax+by=c becomes ax=c. that means that x = c/a. 0/1 = 0.
  • Y intercept is found by setting x to 0: the equation becomes by=c, and therefore y = c/b. Y intercept is 0/-1 = 0.
  • Slope is -1/-1 = 1.
  • Equation in slope-intercept form: y=1*x+0.
\"graph%28+500%2C+500%2C+0-8%2C+0%2B8%2C+0-8%2C+0%2B8%2C+1%2Ax%2B0+%29+\"\n" ); document.write( "
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