document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=430947>Question 430947</A>: <I><SPAN STYLE=\"word-break: break-all;\"> identify the foci,of the following ellipse. sketch each.\r<BR>\n" );
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document.write( "1. (x-1)^2/25 + (y+2)^2/16 = 1<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #299202 by </B><A HREF=/tutors/aboutme.mpl?userid=Gogonati><B>Gogonati(855)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Gogonati><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Gogonati><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=299202\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solution: The center of this ellipse is the point (1, -2), a^2=25 and b^2=16\r<BR>\n" );
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document.write( "As we know c^2=a^2-b^2=25-16=9, thus, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=c%5E2=9 ALIGN=MIDDLE  ALT=\"c%5E2=9\"   DISABLED_style= \"max-width:90%; height:auto;\" >, And c=/- sqrt(9)\r<BR>\n" );
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document.write( "c=-3 and c=3, hence the coordinates of the foci will be:(-3,0) and (3,0),when the  ellipse was centered at (0, 0), Our ellipse was shifted at poit (1, -2), thus the new foci will be:(-3+1, 0-2) and (3+1, 0-2), simplify: (-2, -2) and (4, -2).\r<BR>\n" );
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document.write( "Answer: the foci of ellipse are: (-2, -2) and (4, -2)\r<BR>\n" );
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document.write( "Done. </SPAN>\n" );
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