document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=430866>Question 430866</A>: <I><SPAN STYLE=\"word-break: break-all;\"> John bought a radio for $120. He paid his bill with two dollar bills and five dollar bills. If there were 30 bills in all how many of each were there? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #299156 by </B><A HREF=/tutors/aboutme.mpl?userid=Gogonati><B>Gogonati(855)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Gogonati><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Gogonati><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=299156\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solution:Let x the number of $5 bills, then 30-x is the number of $2 bills\r<BR>\n" );
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document.write( "Since he spend $120 we write: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5x%2B2%2830-x%29=120 ALIGN=MIDDLE  ALT=\"5x%2B2%2830-x%29=120\"   DISABLED_style= \"max-width:90%; height:auto;\" >, solve the equation.\r<BR>\n" );
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document.write( "5x-2x=120-60 => 3x=60 => x=20.\r<BR>\n" );
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document.write( "Answer:John bought the radio with 20, $5 bills and 30-20=10, $2 bills.\r<BR>\n" );
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document.write( "Check: 20X5+10X2=100+20=120.\r<BR>\n" );
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document.write( "Done. </SPAN>\n" );
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