document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=430872>Question 430872</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of three times the number and a second number is one. The difference of the first number minus the second number is seven. Find these numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #299144 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=299144\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The sum of three times the number and a second number is one. The difference of the first number minus the second number is seven. Find these numbers<BR>\n" );
document.write( "..<BR>\n" );
document.write( "let x=first number<BR>\n" );
document.write( "let y=second number\r<BR>\n" );
document.write( "\n" );
document.write( "3x+y=1<BR>\n" );
document.write( "x-y=7<BR>\n" );
document.write( "y=x-7<BR>\n" );
document.write( "3x+x-7=1<BR>\n" );
document.write( "4x=8<BR>\n" );
document.write( "x=2<BR>\n" );
document.write( "y=x-7=2-7=-5<BR>\n" );
document.write( "ans:<BR>\n" );
document.write( "numbers are: 2 and -5 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );