document.write( "Question 430859: PROBLEM 1
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document.write( "A total of $25,000 is invested in two funds paying 4% and 4.5% simple interest. The annual interest is $1060. How much is invested in each fund?\r
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document.write( "PROBLEM 2
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document.write( "Find the dimensions of the rectangle meeting the specified conditions.
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document.write( "Perimeter Condition
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document.write( "360 inches The width is 40 inches less than the length.
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Algebra.Com's Answer #299140 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Part I 4.00% per annum \n" ); document.write( "Part II 4.50% per annum \n" ); document.write( " \n" ); document.write( "x+y=25000 ------------------------1 \n" ); document.write( "4.00%x+4.50%y=$1,060.00 \n" ); document.write( "Multiply by 100 \n" ); document.write( "4x+4.5y=$106,000.00 --------2 \n" ); document.write( " \n" ); document.write( "Multiply (1) by -4 \n" ); document.write( "we get \n" ); document.write( " \n" ); document.write( "-4x-4y=-100000.00 \n" ); document.write( " \n" ); document.write( "Add this to (2) \n" ); document.write( " \n" ); document.write( "0.5y=$6,000.00 \n" ); document.write( " \n" ); document.write( "divide by0.5 \n" ); document.write( " \n" ); document.write( "y=$12,000.00 investment at 4.50% \n" ); document.write( "Balance $13,000.00 investment at 4.00% \n" ); document.write( "...............\r \n" ); document.write( "\n" ); document.write( "Length = l \n" ); document.write( "width =l-40 \n" ); document.write( "perimeter = 2*(l+w) \n" ); document.write( "Perimeter = 2(l+l-40) \n" ); document.write( "Perimeter = 4l-80 \n" ); document.write( "360= 4l-80 \n" ); document.write( "4l=440 \n" ); document.write( "l=110 in \n" ); document.write( "width = 70 in \n" ); document.write( " |