document.write( "Question 430859: PROBLEM 1
\n" ); document.write( "A total of $25,000 is invested in two funds paying 4% and 4.5% simple interest. The annual interest is $1060. How much is invested in each fund?\r
\n" ); document.write( "\n" ); document.write( "PROBLEM 2
\n" ); document.write( "Find the dimensions of the rectangle meeting the specified conditions.
\n" ); document.write( "Perimeter Condition
\n" ); document.write( "360 inches The width is 40 inches less than the length.
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Algebra.Com's Answer #299140 by mananth(16946)\"\" \"About 
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Part I 4.00% per annum
\n" ); document.write( "Part II 4.50% per annum
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\n" ); document.write( "x+y=25000 ------------------------1
\n" ); document.write( "4.00%x+4.50%y=$1,060.00
\n" ); document.write( "Multiply by 100
\n" ); document.write( "4x+4.5y=$106,000.00 --------2
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\n" ); document.write( "Multiply (1) by -4
\n" ); document.write( "we get
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\n" ); document.write( "-4x-4y=-100000.00
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\n" ); document.write( "Add this to (2)
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\n" ); document.write( "0.5y=$6,000.00
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\n" ); document.write( "divide by0.5
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\n" ); document.write( "y=$12,000.00 investment at 4.50%
\n" ); document.write( "Balance $13,000.00 investment at 4.00%
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\n" ); document.write( "\n" ); document.write( "Length = l
\n" ); document.write( "width =l-40
\n" ); document.write( "perimeter = 2*(l+w)
\n" ); document.write( "Perimeter = 2(l+l-40)
\n" ); document.write( "Perimeter = 4l-80
\n" ); document.write( "360= 4l-80
\n" ); document.write( "4l=440
\n" ); document.write( "l=110 in
\n" ); document.write( "width = 70 in
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