document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=430840>Question 430840</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am stuck on the following question:\r<BR>\n" );
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document.write( "Solve for x in the equation: (1+sinx)/cosx + cosx/(1+sinx) = 4 for 0<=x<=2pi rads\r<BR>\n" );
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document.write( "Any help is appreciated\r<BR>\n" );
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document.write( "Thank You </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #299139 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=299139\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve for x in the equation: (1+sinx)/cosx + cosx/(1+sinx) = 4 for 0<=x<=2pi rads <BR>\n" );
document.write( "..<BR>\n" );
document.write( " (1+sinx)/cosx + cosx/(1+sinx) = 4<BR>\n" );
document.write( "LCD: (cosx)(1+sinx)<BR>\n" );
document.write( "(1+sinx)^2+cos^2x=4(cosx)(1+sinx)<BR>\n" );
document.write( "1+2sinx+sin^2x+cos^2x=4(cosx)(1+sinx)<BR>\n" );
document.write( "sin^2x+cos^2x=1<BR>\n" );
document.write( "2+2sinx=4(cosx)(1+sinx)<BR>\n" );
document.write( "2(1+sinx)=4(cosx)(1+sinx)<BR>\n" );
document.write( "2=4(cosx)<BR>\n" );
document.write( "cosx=2/4=1/2<BR>\n" );
document.write( "x=pi/3 and 5pi/3 (note: cos positive in quadrants I and IV) </SPAN>\n" );
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