document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=430882>Question 430882</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A goldsmith has 80g of an alloy that is 50% pure gold. How many grams of an alloy that is 80% pure gold must be combined with the 80g of alloy that is 50% pure gold to form an alloy that is 72% pure gold? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #299135 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=299135\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> ------	Percent	----------------quantity										<BR>\n" );
document.write( "Alloy 1	50	----------------80								<BR>\n" );
document.write( "Alloy 2	80	----------------x								<BR>\n" );
document.write( "Total	72	----------------80+x					<BR>\n" );
document.write( "50*80+80*x=72(80+x)<BR>\n" );
document.write( "4000+80x=5760+72x					<BR>\n" );
document.write( "80x-72x=5760-4000					<BR>\n" );
document.write( "8x=1760										<BR>\n" );
document.write( "/8									<BR>\n" );
document.write( "x=220	gms	80	%	Alloy 2						<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );