document.write( "Question 45090This question is from textbook INTERMEDIATE ALGEBRA
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\n" ); document.write( "Express as a product: log9√x
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Algebra.Com's Answer #29911 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Express as a product: log9√x \r
\n" ); document.write( "\n" ); document.write( "Don't know if you mean \"9\" to be the base or if you
\n" ); document.write( "want to find log (9sqrtx)\r
\n" ); document.write( "\n" ); document.write( "If you want it to be the base you have:
\n" ); document.write( "log(base 9)sqrtx = (1/2)log(base 9)x\r
\n" ); document.write( "\n" ); document.write( "If you mean log(9sqrtx) you have:
\n" ); document.write( "log9 +(1/2)logx\r
\n" ); document.write( "\n" ); document.write( "Or maybe you mean to change the base from 9 to 10; then you have:
\n" ); document.write( "log(9)sqrt= (logsqrtx)/log9 = (1/2)logx/log9\r
\n" ); document.write( "\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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