document.write( "Question 430767: Two angles are complementary. The measure of one angle is 2° more than three times the measure of the other. Find the measure of each angle. \n" ); document.write( "
Algebra.Com's Answer #299103 by oberobic(2304)\"\" \"About 
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Let A and B be the angles.
\n" ); document.write( "They're complementary, so we know: A+B = 90
\n" ); document.write( "The problem also states that one angle is 2 degrees more than 3 times the other angle.
\n" ); document.write( "A = 3B + 2
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\n" ); document.write( "Since A+B=90
\n" ); document.write( "B = 90-A
\n" ); document.write( "A = 90-B
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\n" ); document.write( "Substituting
\n" ); document.write( "90-B = 3B+2
\n" ); document.write( "Add B to both sides
\n" ); document.write( "90 = 4B +2
\n" ); document.write( "Subtract 2 from both sides
\n" ); document.write( "88 = 4B
\n" ); document.write( "so
\n" ); document.write( "4B = 88
\n" ); document.write( "Divide both sides by 4
\n" ); document.write( "B = 22
\n" ); document.write( ".
\n" ); document.write( "Substitute back into a prior equation to find A
\n" ); document.write( "A = 90 - B
\n" ); document.write( "A = 90 - 22
\n" ); document.write( "A = 68
\n" ); document.write( ".
\n" ); document.write( "Always check your work.
\n" ); document.write( "Use the first equation to see if it is true
\n" ); document.write( "A = 3B + 2 ?
\n" ); document.write( "68 = 3(22) + 2 ?
\n" ); document.write( "68 = 66 + 2
\n" ); document.write( "True
\n" ); document.write( ".
\n" ); document.write( "Now re-read the question to make sure you answer it.
\n" ); document.write( "Answer: The measures of the two angles are 68 degrees and 22 degrees.
\n" ); document.write( ".
\n" ); document.write( "Done.
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