document.write( "Question 430767: Two angles are complementary. The measure of one angle is 2° more than three times the measure of the other. Find the measure of each angle. \n" ); document.write( "
Algebra.Com's Answer #299103 by oberobic(2304)![]() ![]() ![]() You can put this solution on YOUR website! Let A and B be the angles. \n" ); document.write( "They're complementary, so we know: A+B = 90 \n" ); document.write( "The problem also states that one angle is 2 degrees more than 3 times the other angle. \n" ); document.write( "A = 3B + 2 \n" ); document.write( ". \n" ); document.write( "Since A+B=90 \n" ); document.write( "B = 90-A \n" ); document.write( "A = 90-B \n" ); document.write( ". \n" ); document.write( "Substituting \n" ); document.write( "90-B = 3B+2 \n" ); document.write( "Add B to both sides \n" ); document.write( "90 = 4B +2 \n" ); document.write( "Subtract 2 from both sides \n" ); document.write( "88 = 4B \n" ); document.write( "so \n" ); document.write( "4B = 88 \n" ); document.write( "Divide both sides by 4 \n" ); document.write( "B = 22 \n" ); document.write( ". \n" ); document.write( "Substitute back into a prior equation to find A \n" ); document.write( "A = 90 - B \n" ); document.write( "A = 90 - 22 \n" ); document.write( "A = 68 \n" ); document.write( ". \n" ); document.write( "Always check your work. \n" ); document.write( "Use the first equation to see if it is true \n" ); document.write( "A = 3B + 2 ? \n" ); document.write( "68 = 3(22) + 2 ? \n" ); document.write( "68 = 66 + 2 \n" ); document.write( "True \n" ); document.write( ". \n" ); document.write( "Now re-read the question to make sure you answer it. \n" ); document.write( "Answer: The measures of the two angles are 68 degrees and 22 degrees. \n" ); document.write( ". \n" ); document.write( "Done. \n" ); document.write( " |