document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=430751>Question 430751</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the current I in an electrical conductor varies inversely as the resistance R of the conductor. If the current is 1/2 ampere when the resistance is 240 ohms, what is the current when the resistance is 540 ohms? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #299089 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=299089\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I = V/R (using V for voltage, Ohm's law)\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F2+=+V%2F240 ALIGN=MIDDLE  ALT=\"1%2F2+=+V%2F240\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=V+=+120 ALIGN=MIDDLE  ALT=\"V+=+120\"   DISABLED_style= \"max-width:90%; height:auto;\" > volts\r<BR>\n" );
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document.write( "Then, the current at 540 ohms resistance will be <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=I%5B2%5D+=+120%2F540+=+2%2F9 ALIGN=MIDDLE  ALT=\"I%5B2%5D+=+120%2F540+=+2%2F9\"   DISABLED_style= \"max-width:90%; height:auto;\" > ampere\r<BR>\n" );
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