document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=430751>Question 430751</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the current I in an electrical conductor varies inversely as the resistance R of the conductor. If the current is 1/2 ampere when the resistance is 240 ohms, what is the current when the resistance is 540 ohms? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #299083 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=299083\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the current I in an electrical conductor varies inversely as the resistance R of the conductor.<BR>\n" );
document.write( "---<BR>\n" );
document.write( "I = k/R<BR>\n" );
document.write( "---<BR>\n" );
document.write( "Solve for \"k\" using \"the current is 1/2 ampere when the resistance is 240 ohms\"<BR>\n" );
document.write( "(1/2) = k/240<BR>\n" );
document.write( "k = 120<BR>\n" );
document.write( "---<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "I = 120/R<BR>\n" );
document.write( "----<BR>\n" );
document.write( "What is the current when the resistance is 540 ohms?<BR>\n" );
document.write( "I = 120/540<BR>\n" );
document.write( "I = 2/9<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "==================<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );