document.write( "Question 430704: The length of a rectanle is fixed at 25 cm. What widths will make the perimeter greater than 92 cm? The width must be greater than ? Cm. \n" ); document.write( "
Algebra.Com's Answer #299058 by oberobic(2304)\"\" \"About 
You can put this solution on YOUR website!
Start with what you know.
\n" ); document.write( "First, a rectangle has a perimeter = 2L + 2W.
\n" ); document.write( "Second, L=25 is a constant.
\n" ); document.write( "Third, you want the perimeter, P = 92 or P > 92.
\n" ); document.write( ".
\n" ); document.write( "P = 2L + 2W
\n" ); document.write( "Substitute what you know
\n" ); document.write( "92 = 2(25) + 2W
\n" ); document.write( "92 = 50 + 2W
\n" ); document.write( "Divide through by 2
\n" ); document.write( "46 = 25 + W
\n" ); document.write( "Subract 25 from both sides
\n" ); document.write( "21 = W
\n" ); document.write( "or
\n" ); document.write( "W = 21
\n" ); document.write( ".
\n" ); document.write( "Always check your answer.
\n" ); document.write( "2L + 2W = ??
\n" ); document.write( "2(25) + 2(21) = 50 + 42 = 92
\n" ); document.write( ".
\n" ); document.write( "That checks. The value of W = 21 will make the perimeter exactly 92.
\n" ); document.write( ".
\n" ); document.write( "Now make sure you answer the question. It wants the value of W to ensure the perimeter is > 92.
\n" ); document.write( ".
\n" ); document.write( "Answer: W must be greater than 21.
\n" ); document.write( ".
\n" ); document.write( "Done.
\n" ); document.write( "
\n" );