document.write( "Question 430704: The length of a rectanle is fixed at 25 cm. What widths will make the perimeter greater than 92 cm? The width must be greater than ? Cm. \n" ); document.write( "
Algebra.Com's Answer #299058 by oberobic(2304)![]() ![]() ![]() You can put this solution on YOUR website! Start with what you know. \n" ); document.write( "First, a rectangle has a perimeter = 2L + 2W. \n" ); document.write( "Second, L=25 is a constant. \n" ); document.write( "Third, you want the perimeter, P = 92 or P > 92. \n" ); document.write( ". \n" ); document.write( "P = 2L + 2W \n" ); document.write( "Substitute what you know \n" ); document.write( "92 = 2(25) + 2W \n" ); document.write( "92 = 50 + 2W \n" ); document.write( "Divide through by 2 \n" ); document.write( "46 = 25 + W \n" ); document.write( "Subract 25 from both sides \n" ); document.write( "21 = W \n" ); document.write( "or \n" ); document.write( "W = 21 \n" ); document.write( ". \n" ); document.write( "Always check your answer. \n" ); document.write( "2L + 2W = ?? \n" ); document.write( "2(25) + 2(21) = 50 + 42 = 92 \n" ); document.write( ". \n" ); document.write( "That checks. The value of W = 21 will make the perimeter exactly 92. \n" ); document.write( ". \n" ); document.write( "Now make sure you answer the question. It wants the value of W to ensure the perimeter is > 92. \n" ); document.write( ". \n" ); document.write( "Answer: W must be greater than 21. \n" ); document.write( ". \n" ); document.write( "Done. \n" ); document.write( " |