document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=430619>Question 430619</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How much pure gold should be melted into 5 grams of a 62% gold alloy to make it an 85% gold alloy? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #299029 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=299029\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How much pure gold should be melted into 5 grams of a 62% gold alloy to make it an 85% gold alloy?<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "gold + gold = gold<BR>\n" );
document.write( "0.62*5 + 1.00x = 0.85*(5+x)<BR>\n" );
document.write( "Multiply thru by 100:<BR>\n" );
document.write( "62*5 + 100x = 85*5+85x<BR>\n" );
document.write( "15x = 23*5<BR>\n" );
document.write( "x = (1/3)23<BR>\n" );
document.write( "x = 7 2/3 oz (amt. of pure gold needed)<BR>\n" );
document.write( "===========================================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );