document.write( "Question 430486: the radiator in a certain make care needs to contain 40 liters of 40% antifreeze. the radiator now contains 40 liters of 20% antifreeze. how many liters of this solution must be drained and replaced with 100% antifreeze to get the desired strength? \n" ); document.write( "
Algebra.Com's Answer #298966 by stanbon(75887)\"\" \"About 
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the radiator in a certain make care needs to contain 40 liters of 40% antifreeze. the radiator now contains 40 liters of 20% antifreeze. how many liters of this solution must be drained and replaced with 100% antifreeze to get the desired strength?
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\n" ); document.write( "Equation:
\n" ); document.write( "alcohol - alcohol + alcohol = alcohol
\n" ); document.write( "0.20*40 - 0.20x + 1.00x = 0.40*40
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\n" ); document.write( "Multiply thru by 100 to get:
\n" ); document.write( "20*40 - 20x + 100x = 40*40
\n" ); document.write( "80x = 20*40
\n" ); document.write( "x = 10 liters (amt. of liquid to drain and replace_
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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