document.write( "Question 430486: the radiator in a certain make care needs to contain 40 liters of 40% antifreeze. the radiator now contains 40 liters of 20% antifreeze. how many liters of this solution must be drained and replaced with 100% antifreeze to get the desired strength? \n" ); document.write( "
Algebra.Com's Answer #298966 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! the radiator in a certain make care needs to contain 40 liters of 40% antifreeze. the radiator now contains 40 liters of 20% antifreeze. how many liters of this solution must be drained and replaced with 100% antifreeze to get the desired strength? \n" ); document.write( "---------------------------- \n" ); document.write( "Equation: \n" ); document.write( "alcohol - alcohol + alcohol = alcohol \n" ); document.write( "0.20*40 - 0.20x + 1.00x = 0.40*40 \n" ); document.write( "--- \n" ); document.write( "Multiply thru by 100 to get: \n" ); document.write( "20*40 - 20x + 100x = 40*40 \n" ); document.write( "80x = 20*40 \n" ); document.write( "x = 10 liters (amt. of liquid to drain and replace_ \n" ); document.write( "========== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "========== \n" ); document.write( " |