document.write( "Question 430443: hello, my problem here is as follows;\r
\n" ); document.write( "\n" ); document.write( "10+8q=3q^2
\n" ); document.write( "=(-3q)^2+8q+10
\n" ); document.write( "= -(-3q)+/- squared root of (-3)^2-4X(-3)X10/2X(-3)
\n" ); document.write( " {9-(-120)}
\n" ); document.write( "=-(-3) +/- squared root of 129/-6
\n" ); document.write( "= -21.5\r
\n" ); document.write( "\n" ); document.write( "i am stuck at one of these steps that i have done (i am unsure of which one)
\n" ); document.write( "because a negative integer cannot be square rooted.
\n" ); document.write( "please help me, thank you very much for your time and effort, it is greatly appreciated!\r
\n" ); document.write( "\n" ); document.write( "sincerely,
\n" ); document.write( "lost 15 year old
\n" ); document.write( "

Algebra.Com's Answer #298950 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
10+8q=3q^2
\n" ); document.write( "rewrite the equation in ax^2 +bx +c form
\n" ); document.write( "3q^2-8q-10
\n" ); document.write( "compare with ax^2+bx+c
\n" ); document.write( "a= 3 ,b= -8 ,c= -10
\n" ); document.write( "
\n" ); document.write( "b^2-4ac= 64 + 120
\n" ); document.write( "b^2-4ac= 184
\n" ); document.write( "\"q=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29\"
\n" ); document.write( "\"q1=%28-b%2Bsqrt%28b%5E2-4ac%29%29%2F%282a%29\"
\n" ); document.write( "\"q1=%288%2Bsqrt%28184%29%29%2F%286%29\"
\n" ); document.write( "q1=(8+13.56)/6
\n" ); document.write( "q1=3.59
\n" ); document.write( "q2=(8-13.56)/6
\n" ); document.write( "q2= -0.93
\n" ); document.write( "
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