document.write( "Question 430443: hello, my problem here is as follows;\r
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document.write( "10+8q=3q^2
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document.write( "=(-3q)^2+8q+10
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document.write( "= -(-3q)+/- squared root of (-3)^2-4X(-3)X10/2X(-3)
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document.write( " {9-(-120)}
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document.write( "=-(-3) +/- squared root of 129/-6
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document.write( "= -21.5\r
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document.write( "i am stuck at one of these steps that i have done (i am unsure of which one)
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document.write( "because a negative integer cannot be square rooted.
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document.write( "please help me, thank you very much for your time and effort, it is greatly appreciated!\r
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document.write( "sincerely,
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document.write( "lost 15 year old \n" );
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Algebra.Com's Answer #298950 by mananth(16946)![]() ![]() You can put this solution on YOUR website! 10+8q=3q^2 \n" ); document.write( "rewrite the equation in ax^2 +bx +c form \n" ); document.write( "3q^2-8q-10 \n" ); document.write( "compare with ax^2+bx+c \n" ); document.write( "a= 3 ,b= -8 ,c= -10 \n" ); document.write( " \n" ); document.write( "b^2-4ac= 64 + 120 \n" ); document.write( "b^2-4ac= 184 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "q1=(8+13.56)/6 \n" ); document.write( "q1=3.59 \n" ); document.write( "q2=(8-13.56)/6 \n" ); document.write( "q2= -0.93 \n" ); document.write( " \n" ); document.write( " |