document.write( "Question 430397: y=\r
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document.write( "For this equation I need to give the domain, asymptotes, and removable discontinuities. I get both of the asymptotes but I just have no idea what the domain and removable discontinuities are. :( Please help me! Thank you and have a great day!! \n" );
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Algebra.Com's Answer #298948 by robertb(5830) You can put this solution on YOUR website! One restriction on the value of x is that it should not be equal to 0. Another restriction is that \n" ); document.write( "\n" ); document.write( "The DOMAIN is then all real numbers not equal to 0 or 2. This said, \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "As x goes to infinity, the expression goes to y = 0, because the degree of the numerator is less than the degree of the denominator. (Because the expression will have no real roots.) \r \n" ); document.write( "\n" ); document.write( "Hence y = 0 is a HORIZONTAL ASYMPTOTE. \r \n" ); document.write( "\n" ); document.write( "Since the denominator is a quadratic irreducible over the real numbers, the expression has NO VERTICAL ASYMPTOTES.\r \n" ); document.write( "\n" ); document.write( "There are REMOVABLE DISCONTINUITIES at x = 0 and x = 2, because they cancel out in the process of simplification. They correspond to \"holes\" at the graph at the point (0,1) and (2, 2/3). \n" ); document.write( " |