document.write( "Question 430427: (3500)*(1.08)^X=14000*(1.03)^X\r
\n" );
document.write( "\n" );
document.write( "can you please explain how to solve it? Thanks! \n" );
document.write( "
Algebra.Com's Answer #298937 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! (3500)*(1.08)^X=14000*(1.03)^X \n" ); document.write( ".. \n" ); document.write( "(1.08)^x/(1.03)^x=14000/3500=4 \n" ); document.write( "(1.08/1.03)^x=4 \n" ); document.write( "take logs of both sides \n" ); document.write( "xlog(1.08/1.03)=log4 \n" ); document.write( "x(log1.08-log1.03)=log4 \n" ); document.write( "x=log4/(log1.08-log1.03)=29.2453.. \n" ); document.write( " |