document.write( "Question 430407: Give exact and approximate solution to three decimal places. (x+5)^2=4. I don't under stand the three decimal places
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Algebra.Com's Answer #298923 by sudhanshu_kmr(1152)\"\" \"About 
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(x+5)^2=4\r
\n" ); document.write( "\n" ); document.write( "=> x^2 + 10x + 25 = 4\r
\n" ); document.write( "\n" ); document.write( "=> x^2 + 10x + 21 = 0\r
\n" ); document.write( "\n" ); document.write( "=> x^2 + 7x + 3x + 21 = 0\r
\n" ); document.write( "\n" ); document.write( "=> x(x+7) + 3(x +7) =0 \r
\n" ); document.write( "\n" ); document.write( "=> (x+3)(x+7) = 0\r
\n" ); document.write( "\n" ); document.write( "so, x = -3 or x= -7 \r
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