document.write( "Question 428471: I need to use substitution method
\n" ); document.write( "15x-10y=1
\n" ); document.write( "5y=-2+15x \n" ); document.write( "

Algebra.Com's Answer #298915 by mananth(16946) $\"\"$ $\"About$

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15 x + -10 y = 1 .............1
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\n" ); document.write( "5 y = -2 15 x ---------2
\n" ); document.write( "/ 5 =
\n" ); document.write( " y = -0.4 3 x
\n" ); document.write( "Plug the value of y in (1)
\n" ); document.write( "15x-10(-0.4+3x)
\n" ); document.write( "15x+4-30x=1
\n" ); document.write( "15x-30x=1-4
\n" ); document.write( "-15x=-3
\n" ); document.write( "/-15
\n" ); document.write( "x=0.2
\n" ); document.write( "Plug the value of x in (1)
\n" ); document.write( "15x-10y=1
\n" ); document.write( "15*0.2-10y=1
\n" ); document.write( "3-10y=1
\n" ); document.write( "-10y=-2
\n" ); document.write( "/-10
\n" ); document.write( "y=0.2
\n" ); document.write( " \n" ); document.write( "

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