document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=430382>Question 430382</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Ruby is three years older than Sam. Sum of their age is 33. How old are both of them?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #298891 by </B><A HREF=/tutors/aboutme.mpl?userid=Lstark01><B>Lstark01(4)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Lstark01><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=298891\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let R=Ruby, S=Sam. The two equations you will use are R=S+3 and R+S=33. Since R is already solved, use the substitution method and place it in the second equation:<BR>\n" );
document.write( "(S+3)+S=33<BR>\n" );
document.write( "2S+3=33<BR>\n" );
document.write( "-3 on both sides<BR>\n" );
document.write( "2S=30<BR>\n" );
document.write( "Divide by 2 on both sides<BR>\n" );
document.write( "S=15\r<BR>\n" );
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document.write( "Then, if you place S=15 into either equation, you can solve for R.\r<BR>\n" );
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document.write( "R=15+3<BR>\n" );
document.write( "R=18\r<BR>\n" );
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document.write( "or\r<BR>\n" );
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document.write( "R+15=33<BR>\n" );
document.write( "-15 on both sides<BR>\n" );
document.write( "R=18 </SPAN>\n" );
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