document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=44946>Question 44946</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve:\r<BR>\n" );
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document.write( "(&#8730;3x+6)+4<or= 7. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #29886 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=29886\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (&#8730;3x+6)+4<=7<BR>\n" );
document.write( "Since 3x+6 must not be negative, 3x+6>=0, x>=-2<BR>\n" );
document.write( "Keep that in mind.<BR>\n" );
document.write( "Subtract 4 from both sides of the original problem to get:<BR>\n" );
document.write( "sqrt(3x+6)<=3<BR>\n" );
document.write( "Square both sides to get:<BR>\n" );
document.write( "3x+6<= 9<BR>\n" );
document.write( "Subtract 6 from both sides to get:<BR>\n" );
document.write( "3x<=3<BR>\n" );
document.write( "Divide both sides by 3 to get:<BR>\n" );
document.write( "x<=1<BR>\n" );
document.write( "Final Answer: -2<= x <=1<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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