document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=430306>Question 430306</A>: <I><SPAN STYLE=\"word-break: break-all;\"> write the equation in logarithmic form<BR>\n" );
document.write( "2x = 128<BR>\n" );
document.write( "216 1/3 = 6 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #298837 by </B><A HREF=/tutors/aboutme.mpl?userid=John10><B>John10(297)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=John10><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=John10><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=298837\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> write the equation in logarithmic form<BR>\n" );
document.write( "2^x = 128<BR>\n" );
document.write( "216^(1/3) = 6<BR>\n" );
document.write( "---------------------<BR>\n" );
document.write( "2^x = 128<BR>\n" );
document.write( "log(2)128 = x (NOTE: log (2)128 means log of base 2 of 128)<BR>\n" );
document.write( "----------------------<BR>\n" );
document.write( "216^(1/3) = 6<BR>\n" );
document.write( "log(216)6 = 1/3(NOTE: log (216)6 means log of base 216 of 6) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );