document.write( "Question 430250: Survey Results reveal that 45% of patients screened for a virus test positive. from a random sample of 35 patients, estimate the probability that
\n" ); document.write( " at most 18 test positive. \n" ); document.write( "

Algebra.Com's Answer #298823 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi
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document.write( "Survey Results reveal that 45% of patients screened for a virus test positive
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document.write( " p = .45  q = .55 
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document.write( "random sample of 35 patients
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document.write( "mean = .55*35 = 16 expected average number to test positive..
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document.write( "SD = sqrt(35*.55*.45) = ~3
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document.write( "P(at most 18 test positive) that is nearly everything left of z=1, or (P = 84%)
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document.write( "Estimate would be somewhat less than that.
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