document.write( "Question 430251: Survey Results reveal that 45% of patients screened for a virus test positive. from a random sample of 35 patients, estimate the probability that
\n" ); document.write( "between 13 and 19 test positive \n" ); document.write( "

Algebra.Com's Answer #298816 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi
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document.write( "Survey Results reveal that 45% of patients screened for a virus test positive
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document.write( " p = .45  q = .55 
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document.write( "random sample of 35 patients
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document.write( "mean = .45*35 = 16 expected average number to test positive..
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document.write( "SD = sqrt(38*.55*.45) = ~3
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document.write( "P(between 13  and 19) = P (-1 > z <1) 1 SD from mean accounts  for 68.2% 
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