document.write( "Question 430259: How fast would you be driving if you went 3 miles in 19 minutes? \r
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document.write( "Thank you very much,\r
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document.write( "Marlene 9/18/36 \n" );
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Algebra.Com's Answer #298805 by rosey51235(30)![]() ![]() You can put this solution on YOUR website! Hi :)\r \n" ); document.write( "\n" ); document.write( "If by how fast you mean in Miles Per Hour, then you would set this up in a proportion. \n" ); document.write( "(/=fraction bar)\r \n" ); document.write( "\n" ); document.write( "3/19=x/60 (3 and x correspond because that is a miles measurement, while 19 and 60 correspond because they are a minutes measurement)\r \n" ); document.write( "\n" ); document.write( "Cross multiply---198x=19x and 3*60=180\r \n" ); document.write( "\n" ); document.write( "19x=180 --- T oget x alone, divide both sides by 19 (19x/19 will cancel the 19's out, leaving x alone)\r \n" ); document.write( "\n" ); document.write( "180/19=9.4737, though I assume you'd round.\r \n" ); document.write( "\n" ); document.write( "So, 3 miles in 19 minutes is 9 MPH. \n" ); document.write( "....That's reeeeeally slow. even the signs for \"keep kids alive\"is faster then that, it's \"keep kids alive, drive 25\"! So yes, 3 miles in 19 minutes=9MPH=very slow.\r \n" ); document.write( "\n" ); document.write( "Hope I helped! :)\r \n" ); document.write( "\n" ); document.write( "-Rose \n" ); document.write( " |