document.write( "Question 430175: The area of a rectangle is 45 square cm. If the length is 4 cm greater than the width, what are the dimension of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #298751 by algebrahouse.com(1659)\"\" \"About 
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\"The area of a rectangle is 45 square cm. If the length is 4 cm greater than the width, what are the dimension of the rectangle?\"\r
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\n" ); document.write( "\n" ); document.write( "x = width
\n" ); document.write( "x + 4 = length {length is 4 greater than width}\r
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\n" ); document.write( "\n" ); document.write( "Area of a rectangle is length x width\r
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\n" ); document.write( "\n" ); document.write( "x(x + 4) = 45 {area = length x width}
\n" ); document.write( "x² + 4x = 45 {used distributive property}
\n" ); document.write( "x² + 4x - 45 = 0 {subtracted 45 from both sides}
\n" ); document.write( "(x + 9)(x - 5) = 0 {factored into two binomials}
\n" ); document.write( "x + 9 = 0 or x - 5 = 0 {set each factor equal to 0}
\n" ); document.write( "x = -9 or x = 5 {solved each equation for x}
\n" ); document.write( "**x {the width} cannot be negative**
\n" ); document.write( "x = 5
\n" ); document.write( "x + 4 = 9 {substituted 5, in for x, into x + 4}\r
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\n" ); document.write( "\n" ); document.write( "width = 5cm and length = 9cm
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\n" ); document.write( "\n" ); document.write( "width
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