document.write( "Question 430167: (a) The equation of the curve is y=2x³-7x²+4x+4. Find the x value of the maximum turning point. The maximum T.P is NOT on the Y axis\r
\n" ); document.write( "\n" ); document.write( "So far I have that dy/dx=6x²-14x+4=0
\n" ); document.write( " divide through by 2 3x²-7x+2=0
\n" ); document.write( " (3x-1)(x-2)=0
\n" ); document.write( " x=1/3 and x=2\r
\n" ); document.write( "\n" ); document.write( " When I sub 2 into y=2x³-7x²+4x+4, I get that y=0 therefore it must be x=1/3. I sub this into y=... and get 124/27.\r
\n" ); document.write( "\n" ); document.write( "I am unsure if this is correct.\r
\n" ); document.write( "\n" ); document.write( "(b) Factorise 2x³-7x²+4x+4. I used synthetic division and got that x=2 so (x-2)
\n" ); document.write( "∴ (x-2)(2x²-5x+2)
\n" ); document.write( " =(x-2)(2x-1)(x-2)\r
\n" ); document.write( "\n" ); document.write( "Now I am stuck. The qusetion is State the co-ordinates of the point A and hence find the values of x for which 2x³-7x²+4x+4<0.\r
\n" ); document.write( "\n" ); document.write( "It may be easier if I email you the question.\r
\n" ); document.write( "\n" ); document.write( "Any help would be greatly appreciated.
\n" ); document.write( "Andrew.\r
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Algebra.Com's Answer #298744 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
 
\n" ); document.write( "Hi
\n" ); document.write( "1) correct on (1/3,124/27)being the maximum turning point |good work
\n" ); document.write( "2) 2x³-7x²+4x+4 = (x-2)(2x^2-3x-2) = (x-2)(2x+1)(x-2) |x= -1/2 and x = 2
\n" ); document.write( " x < -1/2 lends to f(x)< 0
\n" ); document.write( "always recommend sketching the graph..can be extremely helpful.
\n" ); document.write( "can download FREE graph software at
\n" ); document.write( "http://www.padowan.dk.com\r
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