document.write( "Question 430167: (a) The equation of the curve is y=2x³-7x²+4x+4. Find the x value of the maximum turning point. The maximum T.P is NOT on the Y axis\r
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document.write( "So far I have that dy/dx=6x²-14x+4=0
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document.write( " divide through by 2 3x²-7x+2=0
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document.write( " (3x-1)(x-2)=0
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document.write( " x=1/3 and x=2\r
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document.write( " When I sub 2 into y=2x³-7x²+4x+4, I get that y=0 therefore it must be x=1/3. I sub this into y=... and get 124/27.\r
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document.write( "I am unsure if this is correct.\r
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document.write( "(b) Factorise 2x³-7x²+4x+4. I used synthetic division and got that x=2 so (x-2)
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document.write( "∴ (x-2)(2x²-5x+2)
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document.write( " =(x-2)(2x-1)(x-2)\r
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document.write( "Now I am stuck. The qusetion is State the co-ordinates of the point A and hence find the values of x for which 2x³-7x²+4x+4<0.\r
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document.write( "It may be easier if I email you the question.\r
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document.write( "Any help would be greatly appreciated.
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document.write( "Andrew.\r
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Algebra.Com's Answer #298744 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " |