document.write( "Question 430159: Using Spinner to Generate Numbers:\r
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document.write( "(KEEP IN MIND-that the SPINNER has just 3 sides to it using the numbers 1, 2, 3)\r
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document.write( "Suppose the spinner here is spun twice in succession to determine a two-digit number. Giving each of the following.\r
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document.write( "(a) the sample space _______________\r
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document.write( "(b) the probability of an odd number ___________\r
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document.write( "(c) the probability of an number with repeated digits ____________\r
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document.write( "(d) the total number of a greater than 30 ___________\r
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document.write( "(e) the probability of a prime number ___________\r
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document.write( "-My concern about this is if I am understanding this and setting up the formula correctly in order to solve it. Therefore, should I write it as the (a)3/6 (1st spun 1 or 2 or 3, 2nd spun 1 or 2 or 3) (b) 2/6 (odd numbers 1,3) (c)? (d)? (e) 2/6 (prime numbers 2, 3) (I just not sure which way I am supposed to write this damn formula because this stuff always has confused the hell out of me so much, so please help me understand this best as possible and if I am doing this correctly or not at all too.) \n" );
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Algebra.Com's Answer #298734 by stanbon(75887) ![]() You can put this solution on YOUR website! Using Spinner to Generate Numbers: \n" ); document.write( "(KEEP IN MIND-that the SPINNER has just 3 sides to it using the numbers 1, 2, 3) \n" ); document.write( "Suppose the spinner here is spun twice in succession to determine a two-digit number. Giving each of the following. \n" ); document.write( "(a) the sample space \n" ); document.write( "11,12,13,21,22,23,31,32,33 \n" ); document.write( "-------- \n" ); document.write( "(b) the probability of an odd number :: 6/8 = 3/4 \n" ); document.write( "--------- \n" ); document.write( "(c) the probability of an number with repeated digits ::3/8 \n" ); document.write( "(d) the total number of a greater than 30 ::3/8 \n" ); document.write( "(e) the probability of a prime number :: 4/8 = 1/2 \n" ); document.write( "============== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "============== \n" ); document.write( " \n" ); document.write( " |