document.write( "Question 430149: Part of $15,000 is invested at 8% annual interest, and the rest is invested at 6%. After one year, the accounts paid $1,000 in interest. How much was invested at the lower rate? \n" ); document.write( "

Algebra.Com's Answer #298731 by mananth(16946) $\"\"$ $\"About$

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Part I 8.00% per annum
\n" ); document.write( "Part II 6.00% per annum
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\n" ); document.write( "x+y=15000------------------------1
\n" ); document.write( "8.00%x+ 6.00%y=$1,000.00
\n" ); document.write( "Multiply by 100
\n" ); document.write( "8x+6y=$100,000.00--------2
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\n" ); document.write( "Multiply (1) by -8
\n" ); document.write( "we get
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\n" ); document.write( "-8x-8y=-120000.00
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\n" ); document.write( "Add this to (2)
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\n" ); document.write( "-2y=-$20,000.00
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\n" ); document.write( "divide by -2
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\n" ); document.write( "y=$10,000.00 investment at 6.00%
\n" ); document.write( "Balance $5,000.00 investment at 8.00%
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