document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=430115>Question 430115</A>: <I><SPAN STYLE=\"word-break: break-all;\"> t^2+4t-2=0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #298693 by </B><A HREF=/tutors/aboutme.mpl?userid=haileytucki><B>haileytucki(390)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=haileytucki><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=haileytucki><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=298693\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> NOTE: ~ SYMBOLIZES THE SQUARE ROOT OF\r<BR>\n" );
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document.write( "t^(2)+4t-2=0\r<BR>\n" );
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document.write( "Use the quadratic formula to find the solutions.  In this case, the values are a=1, b=4, and c=-2.<BR>\n" );
document.write( "t=(-b\~(b^(2)-4ac))/(2a) where at^(2)+bt+c=0\r<BR>\n" );
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document.write( "Use the standard form of the equation to find a, b, and c for this quadratic.<BR>\n" );
document.write( "a=1, b=4, and c=-2\r<BR>\n" );
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document.write( "Substitute in the values of a=1, b=4, and c=-2.<BR>\n" );
document.write( "t=(-4\~((4)^(2)-4(1)(-2)))/(2(1))\r<BR>\n" );
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document.write( "Simplify the section inside the radical.<BR>\n" );
document.write( "t=(-4\2~(6))/(2(1))\r<BR>\n" );
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document.write( "Simplify the denominator of the quadratic formula.<BR>\n" );
document.write( "t=(-4\2~(6))/(2)\r<BR>\n" );
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document.write( "First, solve the + portion of \.<BR>\n" );
document.write( "t=(-4+2~(6))/(2)\r<BR>\n" );
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document.write( "Factor out the GCF of 2 from each term in the polynomial.<BR>\n" );
document.write( "t=(2(-2)+2(~(6)))/(2)\r<BR>\n" );
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document.write( "Factor out the GCF of 2 from -4+2~(6).<BR>\n" );
document.write( "t=(2(-2+~(6)))/(2)\r<BR>\n" );
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document.write( "Reduce the expression (2(-2+~(6)))/(2) by removing a factor of 2 from the numerator and denominator.<BR>\n" );
document.write( "t=(-2+~(6))\r<BR>\n" );
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document.write( "Remove the parentheses around the expression -2+~(6).<BR>\n" );
document.write( "t=-2+~(6)\r<BR>\n" );
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document.write( "Next, solve the - portion of \.<BR>\n" );
document.write( "t=(-4-2~(6))/(2)\r<BR>\n" );
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document.write( "Factor out the GCF of 2 from each term in the polynomial.<BR>\n" );
document.write( "t=(2(-2)+2(-~(6)))/(2)\r<BR>\n" );
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document.write( "Factor out the GCF of 2 from -4-2~(6).<BR>\n" );
document.write( "t=(2(-2-~(6)))/(2)\r<BR>\n" );
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document.write( "Reduce the expression (2(-2-~(6)))/(2) by removing a factor of 2 from the numerator and denominator.<BR>\n" );
document.write( "t=(-2-~(6))\r<BR>\n" );
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document.write( "Remove the parentheses around the expression -2-~(6).<BR>\n" );
document.write( "t=-2-~(6)\r<BR>\n" );
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document.write( "The final answer is the combination of both solutions.<BR>\n" );
document.write( "t=-2+~(6),-2-~(6)_t= 0.4494897,-4.44949 </SPAN>\n" );
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