document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=430094>Question 430094</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the solution to 5x+7y=-23 and -3x+y=19.    (type an ordered pair)substitution method or elimination?? repost if this is not what you inquired...be more specific please. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #298672 by </B><A HREF=/tutors/aboutme.mpl?userid=haileytucki><B>haileytucki(390)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=haileytucki><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=haileytucki><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=298672\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 5x+7y=-23_-3x+y=19\r<BR>\n" );
document.write( "\n" );
document.write( "Since -3x does not contain the variable to solve for, move it to the right-hand side of the equation by adding 3x to both sides.<BR>\n" );
document.write( "5x+7y=-23_y=3x+19\r<BR>\n" );
document.write( "\n" );
document.write( "Replace all occurrences of y with the solution found by solving the last equation for y.  In this case, the value substituted is 3x+19.<BR>\n" );
document.write( "5x+7(3x+19)=-23_y=3x+19\r<BR>\n" );
document.write( "\n" );
document.write( "Multiply 7 by each term inside the parentheses.<BR>\n" );
document.write( "5x+21x+133=-23_y=3x+19\r<BR>\n" );
document.write( "\n" );
document.write( "Since 5x and 21x are like terms, add 21x to 5x to get 26x.<BR>\n" );
document.write( "26x+133=-23_y=3x+19\r<BR>\n" );
document.write( "\n" );
document.write( "Since 133 does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 133 from both sides.<BR>\n" );
document.write( "26x=-133-23_y=3x+19\r<BR>\n" );
document.write( "\n" );
document.write( "Subtract 23 from -133 to get -156.<BR>\n" );
document.write( "26x=-156_y=3x+19\r<BR>\n" );
document.write( "\n" );
document.write( "Divide each term in the equation by 26.<BR>\n" );
document.write( "(26x)/(26)=-(156)/(26)_y=3x+19\r<BR>\n" );
document.write( "\n" );
document.write( "Simplify the left-hand side of the equation by canceling the common factors.<BR>\n" );
document.write( "x=-(156)/(26)_y=3x+19\r<BR>\n" );
document.write( "\n" );
document.write( "Simplify the right-hand side of the equation by simplifying each term.<BR>\n" );
document.write( "x=-6_y=3x+19\r<BR>\n" );
document.write( "\n" );
document.write( "Replace all occurrences of x with the solution found by solving the last equation for x.  In this case, the value substituted is -6.<BR>\n" );
document.write( "x=-6_y=3(-6)+19\r<BR>\n" );
document.write( "\n" );
document.write( "Multiply 3 by each term inside the parentheses.<BR>\n" );
document.write( "x=-6_y=-18+19\r<BR>\n" );
document.write( "\n" );
document.write( "Add 19 to -18 to get 1.<BR>\n" );
document.write( "x=-6_y=1\r<BR>\n" );
document.write( "\n" );
document.write( "This is the solution to the system of equations.<BR>\n" );
document.write( "x=-6_y=1 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );