document.write( "Question 430092: how many gallons of a 90% antifreeze solution must be mixed with 60 gallons of 10% antifreeze to get a mixture that is 80% antifreeze? \n" ); document.write( "
Algebra.Com's Answer #298668 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! how many gallons of a 90% antifreeze solution must be mixed with 60 gallons of 10% antifreeze to get a mixture that is 80% antifreeze? \n" ); document.write( "------------- \n" ); document.write( "Equation: \n" ); document.write( "alcohol + alcohol = alcohol \n" ); document.write( "0.90x + 0.10*60 = 0.80*(x+60) \n" ); document.write( "---- \n" ); document.write( "Multiply thru by 100: \n" ); document.write( "--- \n" ); document.write( "90x + 10*60 = 80x+80*60 \n" ); document.write( "10x = 70*60 \n" ); document.write( "x = 420 gallons (amt. of 90% solution needed) \n" ); document.write( "============================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "============ \n" ); document.write( " |