document.write( "Question 430092: how many gallons of a 90% antifreeze solution must be mixed with 60 gallons of 10% antifreeze to get a mixture that is 80% antifreeze? \n" ); document.write( "
Algebra.Com's Answer #298668 by stanbon(75887)\"\" \"About 
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how many gallons of a 90% antifreeze solution must be mixed with 60 gallons of 10% antifreeze to get a mixture that is 80% antifreeze?
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\n" ); document.write( "Equation:
\n" ); document.write( "alcohol + alcohol = alcohol
\n" ); document.write( "0.90x + 0.10*60 = 0.80*(x+60)
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\n" ); document.write( "Multiply thru by 100:
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\n" ); document.write( "90x + 10*60 = 80x+80*60
\n" ); document.write( "10x = 70*60
\n" ); document.write( "x = 420 gallons (amt. of 90% solution needed)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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