document.write( "Question 45041: the sum of the squares of two consecutive even integers 1252. find the inetegers \n" ); document.write( "
Algebra.Com's Answer #29866 by abhijitvakil(7)![]() ![]() ![]() You can put this solution on YOUR website! Let the lesser integer be x. Then the other number being consecutive even integer to x, becomes (x + 2). Now the relation given in the problem can be stated as :\r \n" ); document.write( "\n" ); document.write( "x^2 + (x + 2)^2 = 1252\r \n" ); document.write( "\n" ); document.write( "or\r \n" ); document.write( "\n" ); document.write( "x^2 + (x^2 + 2*x*2 + 2^) = 1252 ( we use the formula (a + b)^2 = a^2 + 2ab + b^2) \r \n" ); document.write( "\n" ); document.write( "or\r \n" ); document.write( "\n" ); document.write( "x^2 + x^2 + 4x + 4 = 1252\r \n" ); document.write( "\n" ); document.write( "or\r \n" ); document.write( "\n" ); document.write( "2x^2 + 4x + 4 - 1252 = 0\r \n" ); document.write( "\n" ); document.write( "or\r \n" ); document.write( "\n" ); document.write( "x^2 + 2x - 624 = 0 ..... (1) ( we divide the entire equation by 2)\r \n" ); document.write( "\n" ); document.write( "The above is a typical quadratic equation of the type ax^2 + bx + c = 0. Thus we have\r \n" ); document.write( "\n" ); document.write( "a = 1, b = 2 & c = 624\r \n" ); document.write( "\n" ); document.write( "The solution to this equation is given by the following :\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "substituting the values of a,b, & c into the above, we get two \"roots\" or solutions to x ( i am skipping the numerical calculations, which the student can do himself ):\r \n" ); document.write( "\n" ); document.write( "x = (24, -26)\r \n" ); document.write( "\n" ); document.write( "Thus if x = 24, then the other integer will be x+2 i.e. 26, and if x = -26, then the other integer will be -26+2 i.e. -24. \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |