document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=430036>Question 430036</A>: <I><SPAN STYLE=\"word-break: break-all;\"> picture frame is 22 cm by 15 cm.  If 198 cm2 of picture shows, what would the width of the frame if all sides are even? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #298655 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=298655\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let X equal the width of our frame. 22-2x equals the area inside the frame that shows a picture (It's 2x because we have frame surrounding both sides of the picture). Likewise, its length is 15-2x, since the width of the frame is consistent throughout.  Thus:\r<BR>\n" );
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document.write( "(22-2x)(15-2x)=198<BR>\n" );
document.write( "330-74x+4x2=198<BR>\n" );
document.write( "4x2-74x+132=0<BR>\n" );
document.write( "2x2-37x+66=0<BR>\n" );
document.write( "(2x-33)(x-2)=0\r<BR>\n" );
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document.write( "If we use x=2, we see our equation works. 22-2x=18, 15-2x=11---so our picture is 18X11, which gives us 198cm2, and our frame is 2cm wide. </SPAN>\n" );
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