document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=430057>Question 430057</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jose has 22 coins totaling $4.10. If all of the 22 coins are either nickles or quarters, how many of each coin does he have? You must define the variable first and then solve for variable.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #298633 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=298633\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If Jose has 22 coins, then<BR>\n" );
document.write( "X+Y=22\r<BR>\n" );
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document.write( "If all the coins are either nickles or quarters, then<BR>\n" );
document.write( ".25X+.05Y=4.10\r<BR>\n" );
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document.write( "Multiply the second equation by 100, we get<BR>\n" );
document.write( "25X+5Y=410\r<BR>\n" );
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document.write( "Take the first equation and multiply by 5 we get<BR>\n" );
document.write( "5X+5Y=110\r<BR>\n" );
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document.write( "Subtract the first equation from the second, we get<BR>\n" );
document.write( "20X=300<BR>\n" );
document.write( "X=15\r<BR>\n" );
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document.write( "So we have 15 quarters (X) and 22-15, or 7 nickels (Y). </SPAN>\n" );
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