document.write( "Question 430024: I need to solve this equation algebraically\r
\n" ); document.write( "\n" ); document.write( "sqrt (x+1)= cube root (4x-4) \n" ); document.write( "

Algebra.Com's Answer #298628 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"+sqrt%28x%2B1%29+=+root%283%2C4x-4%29+\"$ Raise each sides to the 6th power
\n" ); document.write( " $\"+%28sqrt%28x+%2B+1%29%29%5E6+=+%28root%283%2C4x-4%29%29%5E6+\"$
\n" ); document.write( " $\"+%28x+%2B+1%29%5E3+=+%284x-4%29%5E2+\"$
\n" ); document.write( " $\"+x%5E3+%2B+3x%5E2+%2B+3x+%2B+1+=+16x%5E2+-+32x+%2B+16+\"$
\n" ); document.write( " $\"+x%5E3+-+13x%5E2+%2B+35x+-+15+=+0+\"$
\n" ); document.write( "This has me stumped.
\n" ); document.write( "I can say $\"+%28+x+-+b+%29%2A%28+x%5E2+%2B+a+%29+=+x%5E3+-+b%2Ax%5E2+%2B+ax+-+a%2Ab+=+0+\"$
\n" ); document.write( "I can say
\n" ); document.write( " $\"a+=+35\"$
\n" ); document.write( " $\"b+=+13\"$
\n" ); document.write( " $\"a%2Ab+=+455\"$
\n" ); document.write( "I'll rewrite the equation
\n" ); document.write( " $\"+x%5E3+-+13x%5E2+%2B+35x+=+15+\"$
\n" ); document.write( "Add $\"455\"$ to both sides
\n" ); document.write( " $\"+x%5E3+-+13x%5E2+%2B+35x+%2B+455+=+470+\"$
\n" ); document.write( " $\"+%28+x+-+13+%29%2A%28+x%5E2+%2B+35+%29+=+470+\"$
\n" ); document.write( "Looking at this, the answer seems to be between
\n" ); document.write( " $\"14\"$ and $\"15\"$ . Maybe you can find a
\n" ); document.write( "cubic equation solver on the internet.\r
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