document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=429946>Question 429946</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi there, I would appreciate some help with the next problem:<BR>\n" );
document.write( "    Kristal can wax a floor in 16 minutes. One day her friend Perry helped her and it only took 5.76 minutes. How long would it take Perry to do it alone? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #298583 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=298583\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Kristal's rate = 1 floor in 16 min. = 1/16 floors per min.<BR>\n" );
document.write( "Working together their rate = 1 floor in 5.76 min. = 1/5.76 floors per min.<BR>\n" );
document.write( "We need to determine Perry's rate, so we need to equate their combined rate with the sum of the individual rates.<BR>\n" );
document.write( "Let Perry's time = x<BR>\n" );
document.write( "In equation form, we can write:<BR>\n" );
document.write( "1/16 + 1/x = 1/5.76<BR>\n" );
document.write( "Solve for x:<BR>\n" );
document.write( "(x+16)/16x = 1/5.76 -> 5.76(x+16) = 16x -> 10.24x = 92.16 -> x = 9<BR>\n" );
document.write( "So, Perry would take 9 mins. to do the floor alone. </SPAN>\n" );
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