document.write( "Question 429938: how much pure acid must be added to 25 ounces of a solution of acid and water that is 20% pure acid in order to make a solution that is 50 % pure acid ? \n" ); document.write( "

Algebra.Com's Answer #298574 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi
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document.write( "Let x represent how much pure acid needs to added to the 20% solution
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document.write( "Question states***
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document.write( "\"make a solution that is 50 % pure acid\" 
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document.write( " 1.0x + .20*25oz = .50(25oz+x)
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document.write( "        .5x = .30*25oz
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document.write( "          x = 15 oz pure acid needs to added to the 20% solution\r
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document.write( "CHECKING our Answer***
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document.write( " 1.0*15oz + .20*25oz = 15oz + 5oz = .5*40 = 20oz (pure acid)\r
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