document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=429904>Question 429904</A>: <I><SPAN STYLE=\"word-break: break-all;\"> piece of wire 42 cm long is bent into a rectangle whose length is twice its width. Find the dimensions of the rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #298570 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=298570\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The perimeter of the rectangle = 2l + 2w<BR>\n" );
document.write( "Given: l = 2w<BR>\n" );
document.write( "So we can write the following equation:<BR>\n" );
document.write( "2(2w) + 2w = 42<BR>\n" );
document.write( "Solve for w:<BR>\n" );
document.write( "6w = 42 -> w = 7<BR>\n" );
document.write( "So the length = 2w = 2(7) = 14<BR>\n" );
document.write( "Ans: length = 14, width = 7 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );