document.write( "Question 429892: Jack usually mows his lawns in 6 hours. Marilyn can mow the same yard in 5 hours. How much time would it take for them to mow the lawn together? \n" ); document.write( "
Algebra.Com's Answer #298556 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Jack usually mows his lawns in 6 hours. Marilyn can mow the same yard in 5 hours. How much time would it take for them to mow the lawn together? \n" ); document.write( "--- \n" ); document.write( "Jack's rate: 1/6 job/hr \n" ); document.write( "Marilyn rate: 1/5 job/hr \n" ); document.write( "Together rate: 1/x job/hr \n" ); document.write( "----- \n" ); document.write( "Equation: \n" ); document.write( "rate + rate = together rate \n" ); document.write( "1/6 + 1/5 = 1/x \n" ); document.write( "---- \n" ); document.write( "Multiply thru by 30x to get: \n" ); document.write( "5x + 6x = 30 \n" ); document.write( "11x = 30 \n" ); document.write( "x = 30/11 = 2 8/11 hrs (time to do the job together) \n" ); document.write( "================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |